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$(13/10+7/8+1/4+2/5)-[(5/4-1/10)+(2+5/8-6/5)]$
| $(13/10+7/8+1/4+2/5)-[(5/4-1/10)+(2+5/8-6/5)]$ | di Alfredo Bochicchio |
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$(52+35+10+16)/40-[(25-2)/20+(80+25-48)/40]$ $113/40-[23/20+57/40]$ $113/40-(46+57)/40$ $113/40-103/40$ $(113-103)/40$ $10/40$ $1/4$
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