[math]1/3 \\log (9x+8-x^3 )=\\log (2-x)[/math]
[math]\\log (9x+8-x^3 )=\\log((2-x)^3)[/math]
[math]9x+8-x^3=8-x^3-12x+6x^2[/math]
[math]-12x+6x^2-9x=0[/math]
[math]-4x+2x^2-3x=0[/math]
[math]x(2x-7)=0[/math]
[math]x=0 ?x=7/2[/math]
[math]x=7/2[/math]
non accettabile[math]x=0[/math]
![Equazioni esponenziali e logaritmiche: [math] {2}\cdot \log{{x}}- \log{{\left({2}{x}+{1}\right)}}+ \log{{3}}= \log{{\left({x}-{2}\right)}} [/math]](https://cdn.skuola.net/shared/thumb/159x141/news_foto/2017/10/equ_log_e3.jpg)
![Equazioni esponenziali e logaritmiche: [math] \frac{6}{{{\left( \log{{x}}\right)}^{2}-{1}}}+\frac{3}{{ \log{{x}}+{1}}}=\frac{{ \log{{x}}+{1}}}{{ \log{{x}}-{1}}} [/math]](https://cdn.skuola.net/shared/thumb/159x141/news_foto/2017/10/equ_log_e2.jpg)
