[math]\frac{3\times(x-3)^2}{4}+\frac{1}{4}+(x+2)^2=\frac{3}{4}x^2-6+(x+1)\times(X-1)+4x[/math]
[math]\frac{3\times(x^2-6x+9)}{4}+\frac{1}{4}+(x^2+4x+4)=\frac{3}{4}x^2-6+(x^2-1)+4x[/math]
[math]\frac{3x^2-18x+27}{4}+\frac{1}{4}+x^2+4x+4=\frac{3}{4}x^2-6+x^2-1+4x[/math]
[math]\frac{3}{4}x^2-\frac{18}{4}+\frac{27}{4}+\frac{1}{4}+4x+4=\frac{3}{4}x^2-6-1+4x[/math]
[math]-\frac{18}{4}x+4x-4x=-6-1-\frac{27}{4}-\frac{1}{4}-4[/math]
[math]-\frac{18}{4}x=-11-7[/math]
[math]x=-18\times(\frac{-4}{8})[/math]
[math]x=4[/math]
