# problema in inglese

When 4200J of heat are added to a 0,15m-long silver bar, its length increases by 4,3*10^-3m. What is the mass of the bar?

SVOLGIMENTO:

$DT= Dl/(l_0*K)= [(4,3*10^-3)/(0,15* 19*10^-6)]°C= 1508,8°C$

$m=Q/(c*DT)= [4200/ (235*1508,8)]Kg= 0,012Kg$

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