$sin(x/2)=1/2$
$cos(x/2)=sqrt(3)/2$
Io ho risolto le due equazioni così:
$sen(x/2)=1/2->x/2=arcsen(1/2)+k180°->x/2=30°+k180°vvx/2=150°+k180°-> x=60°+k360°vvx=$
$300°+k360°$
$cos(x/2)=sqrt(3)/2->x/2=\pm arccos(sqrt(3)/2)+k180°->x/2=\pm30°+k180°->x=\pm60°+k360°$