Testo nascosto, fai click qui per vederlo
Ci sono quindici stati, anzi sedici con lo stato di partenza $S$ e sarebbero
$a=\text(AGM)$
$b=\text(AMG)$
$c=\text(GAM)$
$d=\text(GMA)$
$e=\text(MAG)$
$f=\text(MGA)$
$g=\text(AG)$
$h=\text(AM)$
$i=\text(GA)$
$j=\text(GM)$
$k=\text(MA)$
$l=\text(MG)$
$m=\text(A)$
$n=\text(G)$
$o=\text(M)$
e i "percorsi" possibili dovrebbero essere questi
$S->1/6*a->1*k$
$S->1/6*b->1*k$
$S->1/6*c->1/6*b$
$S->1/6*c->5/6*l$
$S->1/6*d->1/6*e$
$S->1/6*d->5/6*l$
$S->1/6*e->1*a$
$S->1/6*f->1*c$
$g->1*m$
$h->1*m$
$i->1/6*g$
$i->5/6*n$
$j->1/6*l$
$j->5/6*n$
$k->(1-p)*h$
$k->p*o$
$l->(1-p)*j$
$l->p*o$
$m->m$
$n->n$
$o->o$
$a=\text(AGM)$
$b=\text(AMG)$
$c=\text(GAM)$
$d=\text(GMA)$
$e=\text(MAG)$
$f=\text(MGA)$
$g=\text(AG)$
$h=\text(AM)$
$i=\text(GA)$
$j=\text(GM)$
$k=\text(MA)$
$l=\text(MG)$
$m=\text(A)$
$n=\text(G)$
$o=\text(M)$
e i "percorsi" possibili dovrebbero essere questi
$S->1/6*a->1*k$
$S->1/6*b->1*k$
$S->1/6*c->1/6*b$
$S->1/6*c->5/6*l$
$S->1/6*d->1/6*e$
$S->1/6*d->5/6*l$
$S->1/6*e->1*a$
$S->1/6*f->1*c$
$g->1*m$
$h->1*m$
$i->1/6*g$
$i->5/6*n$
$j->1/6*l$
$j->5/6*n$
$k->(1-p)*h$
$k->p*o$
$l->(1-p)*j$
$l->p*o$
$m->m$
$n->n$
$o->o$
S.E.&O.
Cordialmente, Alex