Re: Esercizio su PLANCHEREL
Inviato: 05/04/2020, 14:05Prova cosi:
\(\int_{-\infty }^{+\infty }\left | 5\cdot H\left ( t \right )\cdot e^{-5t} \right |^{2}dt=
25\int_{0}^{\infty }e^{-10t}dt=\frac{5}{2}\)
\(\int_{-\infty }^{+\infty }\left | 5\cdot H\left ( t \right )\cdot e^{-5t} \right |^{2}dt=
25\int_{0}^{\infty }e^{-10t}dt=\frac{5}{2}\)
