da killing_buddha » 15/04/2018, 16:26
Chiaramente non vale. Data una matrice $A$ qualsiasi, diciamo a ingressi reali, che abbia determinante diverso da zero, la matrice \(\frac{1}{\sqrt[n]{|\det A|}}A\) ha determinante 1 o -1.
- "Everything in Mathematics that can be categorized, is trivial" (P. J. Freyd), which should be understood as: "category theory is good ideas rather than complicated techniques".
- "I always disliked Analysis" (P. J. Freyd)