English in math, complex numbers

[Caenorhabditis]

...counted with multiplicity.

Yes, of course.

[Zero87]

A very nice fact about complex numbers is that every equation of $n$-th degree in the complex field has got exactly $n$ solutions. So, the equation
$z^456- \frac{24}{23}z^118+\sqrt{39}z^66-12.5=0$
has got precisely 456 solutions!

...counted with multiplicity.

It is a Theroem which has a nice and simple proof for people who have knowledge of complex analysis...

Then, I want to underline this previous passage of Caenorhabditis (hi! )

So, the equation
$z^456- \frac{24}{23}z^118+\sqrt{39}z^66-12.5=0$
has got precisely 456 solutions!

I remember a nice result which says that if we have $m\ge n+1$ zeroes of a polynomial equation of degree $n$, the polynomial must be equal to zero ($P(x)\equiv 0$).

[Caenorhabditis]

It is a Theroem which has a nice and simple proof for people who have knowledge of complex analysis...

Courant and Robbins (What is mathematics?) gave a very simple proof of this, based on the fixed-point theorem.

[WalterLewin90]

[quote="Zero87"]Hello world, my english is awful, but I try to explaining something useful for you.

Complex numbers may be defined in several ways, but I think the simplest definition is the seguent:
/quote]

"Seguent"? I'm pretty sure that the world "seguent " doesn't exist. Did you mean "following"?

[Zero87]

"Seguent"? I'm pretty sure that the world "seguent " doesn't exist. Did you mean "following"?

I remember a "sketch" of Aldo, Giovanni & Giacomo, in which Giacomo traslated all in english and he used often the word "seguent".