Let $F$ be our finite skew field, $F^**$ its multiplicative group.
Let $S$ be any Sylow subgroup $F^**$, of order, say, $p^a$.
Choose an element $g$ of order $p$ in the center of $S$.
If some $h in S$ generates a subgroup of order $p$ different from that generated by $g$, then $g$ and $h$ generate a commutative field containing more than $p$ roots of the equation $x^p=1$, an impossibility.
Thus $S$ contains only one subgroup of order $p$ and hence is either a cyclic or general quaternion group.
Chi l'ha scritto?
Cordialmente, Alex