$(x+6)/8-(1/3)((x-2)/4+(4-x)/8)=(x-4)/4+(5)/12$

Svolgimento:

$(x+6)/8-(1/3)((2x-4+4-x)/8)=(3x-12+5)/12$

$(x+6)/8-(1/24)x=(3x-7)/12$

$(3x+18-x)/24=(6x-14)/24$

$4x=32$

$x=8$

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