Svolgimento:
$y_(1,2)=(-(-2x)+-sqrt((-2x)^2-4(1)(-1)))/2=>y_(1,2)=(2x+-sqrt(4x^2+4))/2=>$
$=>y_(1,2)=2x+-sqrt(4(x^2+1))/2=>y_(1,2)=(2x+-2sqrt(x^2+1))/2=>y_(1,2)=(2(x+-sqrt(x^2+1)))/2=>$
$=>y_(1,2)=x+-sqrt(x^2+1)$.
$y^2-2xy-1=0$
29 Dicembre 2008
Svolgimento:
$y_(1,2)=(-(-2x)+-sqrt((-2x)^2-4(1)(-1)))/2=>y_(1,2)=(2x+-sqrt(4x^2+4))/2=>$
$=>y_(1,2)=2x+-sqrt(4(x^2+1))/2=>y_(1,2)=(2x+-2sqrt(x^2+1))/2=>y_(1,2)=(2(x+-sqrt(x^2+1)))/2=>$
$=>y_(1,2)=x+-sqrt(x^2+1)$.